Physics Circle home Student Login

Home›Chapters›Thermometry, Thermal Expansion and Calorimetry PYQs›Thermometry & Thermal Expansion›Question 29

MHT CET 2024 (15 May, Shift 1) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from MHT CET 2024 (15 May, Shift 1)

Q29MHT CET 2024 · 15 MAY · SHIFT 1Medium

Thermometry & Thermal Expansion

A sheet of steel is 40 cm long and 5 cm broad at 0∘C0^\circ\text{C}. The surface area of the sheet increases by 1.4 cm21.4\text{ cm}^2 at 100∘C100^\circ\text{C}. Coefficient of linear expansion of steel is

Show answer and solution

Answer: (c)

  1. A=40×5=200 cm2A = 40 \times 5 = 200\text{ cm}^2, β=2α\beta = 2\alpha.
  2. ΔA=A(2α)ΔT⇒1.4=200×2α×100\Delta A = A(2\alpha)\Delta T \Rightarrow 1.4 = 200 \times 2\alpha \times 100
  3. α=1.440000=3.5×10−5/∘C\alpha = \dfrac{1.4}{40000} = 3.5\times10^{-5}/^\circ\text{C}, answer (c).
Report a mistake

More questions on Thermometry & Thermal Expansion