A shell is fired at an angle of 30° to the horizontal with velocity 196 m/s. The time of flight is [sin 30° = 1/2 = cos 60°] (a) 6.5 s (b) 20 s (c) 16.5 s (d) 10 s

Answer: (b). T = (2usin θ)/(g) T = (2 × 196 × 0.5)/(9.8) = 20 s So the answer is (b) 20 s.

A shell is fired at an angle of 30° to the horizontal with velocity… | MHT CET 2022 (11 Aug, Shift 2)

Q19MHT CET 2022 · 11 AUG · SHIFT 2Easy

Time of Flight, Maximum Height & Range

A shell is fired at an angle of $30^\circ$ to the horizontal with velocity $196\text{ m/s}$ . The time of flight is $\left[\sin 30^\circ = \frac{1}{2} = \cos 60^\circ\right]$

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Answer: (b)

$T = \frac{2u\sin\theta}{g}$
$T = \frac{2 \times 196 \times 0.5}{9.8} = 20\text{ s}$
So the answer is (b) 20 s.

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Time of Flight, Maximum Height & Range question from MHT CET 2022 (11 Aug, Shift 2)

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