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NEET 2020 (Phase 1) · Electric Dipole

Electric Dipole question from NEET 2020 (Phase 1)

Q58NEET 2020 · PHASE 1Easy

Electric Dipole

A short electric dipole has a dipole moment of 16 ×\times 10-9 Cm. The electric potential due to the dipole at a point at a distance of 0.6 m from the centre of the dipole, situated on a line making an angle of 60∘60^\circ with the dipole axis is:

(14πε0=9×109 Nm2/C2)\left(\frac{1}{4\pi\varepsilon_0} = 9 \times 10^{9}\text{ Nm}^2/\text{C}^2\right)

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Answer: (a)

  1. Potential of a short dipole: V=kpcos⁡θr2V = \frac{kp\cos\theta}{r^2}
  2. V=9×109×16×10−9×0.50.36=720.36V = \frac{9\times10^9\times16\times10^{-9}\times0.5}{0.36} = \frac{72}{0.36}
  3. V=200V = 200 V, answer (a).
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