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NEET 1992 (AIPMT) · Periodic Motion & SHM Basics

Periodic Motion & SHM Basics question from NEET 1992 (AIPMT)

Q82NEET 1992 · AIPMTEasy

Periodic Motion & SHM Basics

A simple harmonic oscillator has an amplitude AA and time period TT. The time required by it to travel from x=Ax = A to x=A/2x = A/2 is

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Answer: (a)

  1. From the extreme position: x=Acos⁡2πtTx = A\cos\frac{2\pi t}{T}.
  2. A2=Acos⁡2πtT⇒2πtT=π3\frac{A}{2} = A\cos\frac{2\pi t}{T} \Rightarrow \frac{2\pi t}{T} = \frac{\pi}{3}.
  3. t=T6t = \frac{T}{6}.
  4. So the answer is (a) T/6T/6.
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