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MHT CET 2019 (2 May, Shift 2) · Progressive Wave Equation

Progressive Wave Equation question from MHT CET 2019 (2 May, Shift 2)

Q81MHT CET 2019 · 2 MAY · SHIFT 2Easy

Progressive Wave Equation

A simple harmonic progressive wave is represented as y=0.03sin⁡π(2t−0.01x)my = 0.03\sin\pi(2t - 0.01x)\text{m}. At a given instant of time, the phase difference between two particles 25 m apart is

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Answer: (c)

  1. y=0.03sin⁡(2πt−0.01πx)y = 0.03\sin(2\pi t - 0.01\pi x), so k=0.01π m−1k = 0.01\pi\ \text{m}^{-1}.
  2. Δϕ=k Δx=0.01π×25=π4\Delta\phi = k\,\Delta x = 0.01\pi \times 25 = \frac{\pi}{4} rad
  3. So the answer is (c) π4\frac{\pi}{4} rad.
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