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JEE Main 2016 (9 Apr, Shift 1) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from JEE Main 2016 (9 Apr, Shift 1)

Q67JEE Main 2016 · 9 APR · SHIFT 1Medium

Thermometry & Thermal Expansion

A simple pendulum made of a bob of mass m and a metallic wire of negligible mass has time period 2 s at T=0oC. If the temperature of the wire is increased and the corresponding change in its time period is plotted against its temperature, the resulting graph is a line of slope S. If the coefficient of linear expansion of metal is α\alpha then the value of S is:

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Answer: (a)

  1. T=2πL/gT = 2\pi\sqrt{L/g}, so ΔTT=12αθ\dfrac{\Delta T}{T} = \dfrac{1}{2}\alpha\theta.
  2. ΔT=22αθ=αθ\Delta T = \dfrac{2}{2}\alpha\theta = \alpha\theta (with T=2T = 2 s).
  3. Slope S=αS = \alpha, answer (a).
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