Simple Pendulum question from MHT CET 2023 (14 May, Shift 1)

Answer: (b)

1. Tension is maximum at the mean position: $T_{max} = mg + \frac{mv_{max}^2}{l}$.
2. $v_{max} = A\omega = A\sqrt{g/l} \Rightarrow v_{max}^2 = \frac{gA^2}{l}$.
3. $T_{max} = mg + \frac{mgA^2}{l^2} = mg\left[1 + \left(\frac{A}{l}\right)^2\right]$.
4. So the answer is (b).