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MHT CET 2026 (12 May, Shift 2) · Simple Pendulum

Simple Pendulum question from MHT CET 2026 (12 May, Shift 2)

Q15MHT CET 2026 · 12 MAY · SHIFT 2Medium

Simple Pendulum

A simple pendulum of length LL and mass of the bob mm is oscillating with amplitude AA. The maximum tension in the string is (gg = acceleration due to gravity)

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Answer: (c)

  1. Tension is maximum at the mean position: Tmax=mg+mvmax2LT_{max} = mg + \frac{mv_{max}^2}{L}.
  2. vmax=Aω=AgL⇒vmax2=gA2Lv_{max} = A\omega = A\sqrt{\frac{g}{L}} \Rightarrow v_{max}^2 = \frac{gA^2}{L}
  3. Tmax=mg+mgA2L2=mg[1+(AL)2]T_{max} = mg + \frac{mgA^2}{L^2} = mg\left[1 + \left(\frac{A}{L}\right)^2\right]
  4. So the answer is (c).
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