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MHT CET 2020 (16 Oct, Shift 2) · Simple Pendulum

Simple Pendulum question from MHT CET 2020 (16 Oct, Shift 2)

Q69MHT CET 2020 · 16 OCT · SHIFT 2Medium

Simple Pendulum

A simple pendulum of length $l$ has a bob of mass $m$ . It executes SHM of small amplitude A. The maximum tension in the string is ( $g =$ acceleration due to gravity)

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Answer: (b)

At the mean position $T_{max} = mg + \frac{mv_{max}^2}{l}$ , with $v_{max} = A\sqrt{g/l}$ .
$T_{max} = mg + mg\frac{A^2}{l^2}$ .
So the answer is (b) $mg\left(\frac{A^2}{l^2}+1\right)$ .

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