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MHT CET 2024 (10 May, Shift 2) · Simple Pendulum

Simple Pendulum question from MHT CET 2024 (10 May, Shift 2)

Q30MHT CET 2024 · 10 MAY · SHIFT 2Easy

Simple Pendulum

A simple pendulum of length ' $l$ ' has a brass bob attached at its lower end. It's period is ' T '. A steel bob of the same size, having density ' $x$ ' times that of brass, replaces the brass bob. Its length is then so changed that the period becomes ' 2 T '. What is the new length?

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Answer: (c)

$T = 2\pi\sqrt{\frac{l}{g}}$ does not depend on the mass or density of the bob.
$T' = 2T \Rightarrow l' = 2^2 l = 4l$
So the answer is (c) $4l$ .

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