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MHT CET 2024 (11 May, Shift 1) · Simple Pendulum

Simple Pendulum question from MHT CET 2024 (11 May, Shift 1)

Q33MHT CET 2024 · 11 MAY · SHIFT 1Easy

Simple Pendulum

A simple pendulum of length ' $L$ ' has mass ' $M$ ' and it oscillates freely with amplitude ' $A$ '. At extreme position, its potential energy is

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Answer: (d)

At the extreme position all energy is potential: $U = E = \frac{1}{2}M\omega^2A^2$ .
For a simple pendulum $\omega^2 = \frac{g}{L}$ .
$U = \frac{1}{2}M\frac{g}{L}A^2 = \frac{MgA^2}{2L}$
So the answer is (d) $\frac{MgA^2}{2L}$ .

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