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NEET 2023 · Simple Pendulum

Simple Pendulum question from NEET 2023

Q47NEET 2023Easy

Simple Pendulum

A simple pendulum oscillating in air has a period of 3 s\sqrt{3}\text{ s}. If it is completely immersed in non- viscous liquid, having density (14)\left(\frac{1}{4}\right)th of the material of the bob, the new period will be :-

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Answer: (c)

  1. In a liquid: geff=g(1−σρ)=g(1−14)=3g4g_{eff} = g\left(1 - \frac{\sigma}{\rho}\right) = g\left(1 - \frac{1}{4}\right) = \frac{3g}{4}.
  2. T′=3⋅43=2 sT' = \sqrt{3}\cdot\sqrt{\frac{4}{3}} = 2\text{ s}
  3. So the answer is (c) 2 s2\text{ s}.
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