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MHT CET 2025 (26 Apr, Shift 1) · Diffraction at a Single Slit

Diffraction at a Single Slit question from MHT CET 2025 (26 Apr, Shift 1)

Q20MHT CET 2025 · 26 APR · SHIFT 1Medium

Diffraction at a Single Slit

A single slit diffraction pattern is formed with white light. For what wavelength of light the $4$ th secondary maximum in diffraction pattern coincides with the $3$ rd secondary maximum in the pattern of light of wavelength ' $\lambda$ '?

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Answer: (b)

$n$ th secondary maximum: $a\sin\theta = \dfrac{(2n+1)\lambda}{2}$
Coincidence: $\dfrac{9\lambda'}{2} = \dfrac{7\lambda}{2}$ (4th for $\lambda'$ , 3rd for $\lambda$ )
So the answer is (b) $\lambda' = \dfrac{7\lambda}{9}$ .

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