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MHT CET 2024 (4 May, Shift 2) · Diffraction at a Single Slit

Diffraction at a Single Slit question from MHT CET 2024 (4 May, Shift 2)

Q40MHT CET 2024 · 4 MAY · SHIFT 2Medium

Diffraction at a Single Slit

A single slit of width $d$ is illuminated by violet light of wavelength 400 nm and the width of the diffraction pattern is measured as ' Y '. When half of the slit width is covered and illuminated by yellow light of wavelength 600 nm, the width of the diffraction pattern is

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Answer: (c)

Width of pattern (central maximum) $\propto \dfrac{\lambda}{d}$
$\dfrac{Y'}{Y} = \dfrac{600}{400} \times \dfrac{d}{d/2} = 1.5 \times 2 = 3$
So the answer is (c) $3Y$ .

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