Physics Circle home Student Login

Home›Chapters›Alternating Current PYQs›Series LCR Circuit›Question 43

JEE Main 2022 (30 Jul, Shift 2) · Series LCR Circuit

Series LCR Circuit question from JEE Main 2022 (30 Jul, Shift 2)

Q43JEE Main 2022 · 30 JUL · SHIFT 2Medium

Series LCR Circuit

A sinusoidal voltage V(t)=200sin⁡2000tV(t) = 200\sin 2000t volt is applied to a series LCR circuit in which L=10 mH, C=25 μFL = 10\text{ mH},\ C = 25\ \mu\text{F} and R=100 ΩR = 100\ \Omega. The impedance of the circuit is _______ Ω\Omega

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 100

  1. ω=2000 rad/s\omega = 2000\text{ rad/s}
  2. XL=2000×10×10−3=20 ΩX_L = 2000 \times 10\times10^{-3} = 20\ \Omega
  3. XC=12000×25×10−6=20 ΩX_C = \dfrac{1}{2000 \times 25\times10^{-6}} = 20\ \Omega
  4. XL=XCX_L = X_C, so Z=R=100 ΩZ = R = 100\ \Omega.
Report a mistake

More questions on Series LCR Circuit