A small ball of mass m starts at a point A with speed v o and moves along a frictionless track AB as shown. The track BC has coefficient of friction μ. The ball comes to stop at C after travelling a distance L which is: (a) 2h/μ + (v₀²)/(2μ g) (b) h/μ + (v₀²)/(2μ g) (c) h/2μ + (v₀²)/(μ g) (d) h/2μ + (v₀²)/(2μ g)

Answer: (b). From A to C all mechanical energy is used up against friction on BC only. mgh + 1/2mv₀² = μ mgL L = h/μ + (v₀²)/(2μ g) So the answer is (b).

A small ball of mass m starts at a point A with speed v o and moves… | JEE Main 2014 (11 Apr, Shift 1)

Q33JEE Main 2014 · 11 APR · SHIFT 1Medium

Conservation of Energy

A small ball of mass m starts at a point A with speed $v$ o and moves along a frictionless track AB as shown. The track BC has coefficient of friction $\mu$ . The ball comes to stop at C after travelling a distance L which is:

Show answer and solution

Answer: (b)

From A to C all mechanical energy is used up against friction on BC only.
$mgh + \frac{1}{2}mv_0^2 = \mu mgL$
$L = \frac{h}{\mu} + \frac{v_0^2}{2\mu g}$
So the answer is (b).

Report a mistake

Conservation of Energy question from JEE Main 2014 (11 Apr, Shift 1)

More questions on Conservation of Energy