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JEE Main 2020 (9 Jan, Shift 2) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from JEE Main 2020 (9 Jan, Shift 2)

Q66JEE Main 2020 · 9 JAN · SHIFT 2Difficult

Current Loop as a Magnetic Dipole

A small circular loop of conducting wire has radius a and carries current I. It is placed in a uniform magnetic field B perpendicular to its plane such that when rotated slightly about its diameter and released, it starts performing simple harmonic motion of time period T. If the mass of the loop is m then:

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Answer: (d)

  1. Restoring torque for small θ\theta: τ=−mBθ\tau = -mB\theta with m=Iπa2m = I\pi a^2.
  2. Moment of inertia about a diameter: Id=ma22I_d = \frac{ma^2}{2} (mm = mass).
  3. T=2πIdIπa2B=2πm2πIBT = 2\pi\sqrt{\frac{I_d}{I\pi a^2 B}} = 2\pi\sqrt{\frac{m}{2\pi IB}}
  4. T=4π2m2πIB=2πmIBT = \sqrt{\frac{4\pi^2 m}{2\pi IB}} = \sqrt{\frac{2\pi m}{IB}}
  5. So the answer is (d).
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