Physics Circle home Student Login

Home›Chapters›Viscosity PYQs›Terminal Velocity›Question 5

MHT CET 2026 (20 Apr, Shift 2) · Terminal Velocity

Terminal Velocity question from MHT CET 2026 (20 Apr, Shift 2)

Q5MHT CET 2026 · 20 APR · SHIFT 2Easy

Terminal Velocity

A small metal sphere is falling through a viscous liquid. The variation of velocity (VV) with time (tt) is shown correctly in graph

Figure

Show answer and solution

Answer: (c)

  1. At release v=0v = 0, so the graph must start from the origin.
  2. Viscous force 6πηrv6\pi\eta r v grows with vv, so acceleration keeps decreasing: the curve rises with falling slope.
  3. When weight = buoyancy + viscous force, vv becomes constant (terminal velocity): the curve flattens.
  4. This is graph (d), so the answer is option (c).
Report a mistake

More questions on Terminal Velocity