A small metallic sphere of diameter 2 mm and density 10.5 g/cm³ is dropped in glycerine having viscosity 10 Poise and density 1.5 g/cm³ respectively. The terminal velocity attained by the sphere is 3em cm/s. (π = 22/7. and g = 10 m/s²) (a) 1.0 (b) 1.5 (c) 3.0 (d) 2.0

Answer: (d). vt = (2r²(ρ - σ)g)/(9η) (CGS units). r = 0.1 cm, ρ - σ = 9 g/cm³, g = 1000 cm/s², η = 10 P vt = (2 × 0.01 × 9 × 1000)/(9 × 10) = 2 cm/s So the answer is (d) 2.0.

A small metallic sphere of diameter 2 mm and density 10.5 g/cm³ is… | JEE Main 2026 (23 Jan, Shift 2)

Q10JEE Main 2026 · 23 JAN · SHIFT 2Medium

Terminal Velocity

A small metallic sphere of diameter 2 mm and density $10.5\text{ g/cm}^{3}$ is dropped in glycerine having viscosity 10 Poise and density $1.5\text{ g/cm}^{3}$ respectively. The terminal velocity attained by the sphere is $\underline{\hspace{3em}}\text{ cm/s}$ .

$\left(\pi = \frac{22}{7}\right.$ and $g = 10\text{ m/s}^{2})$

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Answer: (d)

$v_t = \dfrac{2r^2(\rho - \sigma)g}{9\eta}$ (CGS units).
$r = 0.1$ cm, $\rho - \sigma = 9\ \text{g/cm}^3$ , $g = 1000\ \text{cm/s}^2$ , $\eta = 10$ P
$v_t = \dfrac{2 \times 0.01 \times 9 \times 1000}{9 \times 10} = 2$ cm/s
So the answer is (d) 2.0.

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Terminal Velocity question from JEE Main 2026 (23 Jan, Shift 2)

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