A small signal voltage V(t) = V0 sin ω t is applied across an ideal capacitor C (a) Current I(t) is in phase with voltage V(t). (b) Current I(t) leads voltage V(t) by 180° (c) Current I(t), lags voltage V(t) by 90°. (d) Over a full cycle the capacitor C does not consume any energy from the voltage source.

Answer: (d). In an ideal capacitor, current leads voltage by 90°, so (a), (b), (c) are wrong. Average power P = VrmsIrmscos 90° = 0. So the capacitor takes no net energy over a full cycle: answer (d).

A small signal voltage V(t) = V0 sin ω t is applied across an ideal… | NEET 2016 (Phase 1)

Q61NEET 2016 · PHASE 1Easy

Pure R, L and C Circuits

A small signal voltage V(t) = V0 sin $\omega$ t is applied across an ideal capacitor C

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Answer: (d)

In an ideal capacitor, current leads voltage by $90^\circ$ , so (a), (b), (c) are wrong.
Average power $P = V_{rms}I_{rms}\cos 90^\circ = 0$ .
So the capacitor takes no net energy over a full cycle: answer (d).

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