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MHT CET 2024 (3 May, Shift 1) · Other SHM Systems

Other SHM Systems question from MHT CET 2024 (3 May, Shift 1)

Q10MHT CET 2024 · 3 MAY · SHIFT 1Easy

Other SHM Systems

A small sphere oscillates simple harmonically in a watch glass whose radius of curvature is 1.6 m. The period of oscillation of the sphere in second is (acceleration due to gravity, $g = 10\text{ m/s}^2$ )

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Answer: (a)

A small sphere in a bowl moves like a pendulum of length $R$ : $T = 2\pi\sqrt{\frac{R}{g}}$ .
$T = 2\pi\sqrt{\frac{1.6}{10}} = 2\pi \times 0.4 = 0.8\pi\text{ s}$
So the answer is (a).

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