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JEE Main 2022 (29 Jun, Shift 2) · Terminal Velocity

Terminal Velocity question from JEE Main 2022 (29 Jun, Shift 2)

Q42JEE Main 2022 · 29 JUN · SHIFT 2Difficult

Terminal Velocity

A small spherical ball of radius 0.1 mm and density 104 kg m−3{}^{-3} falls freely under gravity through a distance h before entering a tank of water. If, after entering the water the velocity of ball does not change and it continue to fall with same constant velocity inside water, then the value of h will be ___________ m.

(Given g = 10 ms−2{}^{-2}, viscosity of water = 1.0 ×\times 10−-5 N-sm−2{}^{-2}).

Numerical answer type. Work it out, then open the answer.

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Answer: 20

  1. Velocity just before entering = terminal velocity in water: 2gh=2r2(ρ−σ)g9η\sqrt{2gh} = \dfrac{2r^2(\rho - \sigma)g}{9\eta}.
  2. r=10−4 mr = 10^{-4}\text{ m}, ρ=104\rho = 10^4, σ=103 kg m−3\sigma = 10^3\text{ kg m}^{-3}, η=10−5 N s m−2\eta = 10^{-5}\text{ N s m}^{-2}.
  3. vt=2×10−8×9×103×109×10−5=20 m/sv_t = \dfrac{2\times10^{-8}\times9\times10^{3}\times10}{9\times10^{-5}} = 20\text{ m/s}
  4. h=vt22g=40020=20 mh = \dfrac{v_t^2}{2g} = \dfrac{400}{20} = 20\text{ m}
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