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JEE Main 2022 (29 Jun, Shift 2) · Equations of Kinematics

Equations of Kinematics question from JEE Main 2022 (29 Jun, Shift 2)

Q19JEE Main 2022 · 29 JUN · SHIFT 2Easy

Equations of Kinematics

A small toy starts moving from the position of rest under a constant acceleration. If it travels a distance of 10m in t s, the distance travelled by the toy in the next t s will be:

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Answer: (c)

From rest $s = \frac{1}{2}at^2$ , so $s \propto t^2$ .
In $2t$ : $s = 4\times 10 = 40\text{ m}$
Distance in the next $t$ s $= 40 - 10 = 30\text{ m}$ . So the answer is (c).

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