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JEE Main 2021 (26 Aug, Shift 1) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from JEE Main 2021 (26 Aug, Shift 1)

Q50JEE Main 2021 · 26 AUG · SHIFT 1Medium

Excess Pressure: Drops & Bubbles

A soap bubble of radius 3 cm is formed inside the another soap bubble of radius 6 cm. The radius of an equivalent soap bubble which has the same excess pressure as inside the smaller bubble with respect to the atmospheric pressure is ................ cm.

Numerical answer type. Work it out, then open the answer.

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Answer: 2

  1. Inside the small bubble: P2−P0=4T3+4T6P_2 - P_0 = \frac{4T}{3} + \frac{4T}{6} (both films add).
  2. Equivalent single bubble: 4Tr=4T(13+16)=4T2\frac{4T}{r} = 4T\left(\frac{1}{3} + \frac{1}{6}\right) = \frac{4T}{2}
  3. r=2 cmr = 2\text{ cm}
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