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MHT CET 2021 (24 Sep, Shift 2) · Ampere's Law, Cylinders, Solenoid & Toroid

Ampere's Law, Cylinders, Solenoid & Toroid question from MHT CET 2021 (24 Sep, Shift 2)

Q42MHT CET 2021 · 24 SEP · SHIFT 2Medium

Ampere's Law, Cylinders, Solenoid & Toroid

A solenoid 2 m long and 4 cm in diameter has 4 layers of windings of 1000 turns each and carries a current of 5 A. What is the magnetic field at its centre along the axis? [μ0=4π×10−7\mu_0 = 4\pi \times 10^{-7} Wb/Am]

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Answer: (c)

  1. Total turns N=4×1000=4000N = 4 \times 1000 = 4000 on L=2L = 2 m, so n=2000n = 2000 turns/m.
  2. B=μ0nI=4π×10−7×2000×5B = \mu_0 n I = 4\pi \times 10^{-7} \times 2000 \times 5
  3. So the answer is (c) 4π×10−34\pi \times 10^{-3} T.
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