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MHT CET 2026 (20 Apr, Shift 2) · Ampere's Law, Cylinders, Solenoid & Toroid

Ampere's Law, Cylinders, Solenoid & Toroid question from MHT CET 2026 (20 Apr, Shift 2)

Q8MHT CET 2026 · 20 APR · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid

A solenoid of 1000 turns is wound uniformly on a glass tube 4 m long and $0.3$ m in diameter. The magnetic intensity at the centre of the solenoid when a current of 4 A flows through it is

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Answer: (d)

Magnetic intensity $H = nI$ , with $n = \dfrac{N}{L} = \dfrac{1000}{4} = 250$ turns/m.
$H = 250 \times 4 = 1000$ A/m.
So the answer is (d) $10^{3}$ A/m.

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