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JEE Main 2019 (8 Apr, Shift 1) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from JEE Main 2019 (8 Apr, Shift 1)

Q94JEE Main 2019 · 8 APR · SHIFT 1Medium

Electric Potential & Equipotentials

A solid conducting sphere, having a charge Q, is surrounded by an uncharged conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of –4 Q, the new potential difference between the same two surfaces is:

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Answer: (a)

  1. Charge on the outer shell raises the potential of every point inside it by the same amount.
  2. So Vsphere−VshellV_{sphere} - V_{shell} depends only on the inner charge: ΔV=kQ(1a−1b)\Delta V = kQ\left(\dfrac1a - \dfrac1b\right).
  3. Adding −4Q-4Q to the shell does not change it.
  4. So the answer is (a) VV.
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