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MHT CET 2026 (18 Apr, Shift 1) · Rolling Motion

Rolling Motion question from MHT CET 2026 (18 Apr, Shift 1)

Q5MHT CET 2026 · 18 APR · SHIFT 1Medium

Rolling Motion

A solid cylinder and a solid sphere having the same mass and radius roll down on the same smooth inclined plane. The ratio of the acceleration of the cylinder $(a_c)$ to that of the sphere $(a_s)$ is

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Answer: (a)

Rolling acceleration: $a = \dfrac{g\sin\theta}{1 + k^2/R^2}$ .
Cylinder: $a_c = \frac{2}{3}g\sin\theta$ ; sphere: $a_s = \frac{5}{7}g\sin\theta$ .
$\dfrac{a_c}{a_s} = \dfrac{2/3}{5/7} = \dfrac{14}{15}$
So the answer is (a).

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