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JEE Main 2023 (1 Feb, Shift 1) · Rolling Motion

Rolling Motion question from JEE Main 2023 (1 Feb, Shift 1)

Q43JEE Main 2023 · 1 FEB · SHIFT 1Medium

Rolling Motion

A solid cylinder is released from rest from the top of an inclined plane of inclination 30∘30^\circ and length 60 cm60\text{ cm}. If the cylinder rolls without slipping, its speed upon reaching the bottom of the inclined plane is __________ ms−1\text{ms}^{-1}. (Given g=10 ms−2g = 10\text{ ms}^{-2})

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Numerical answer type. Work it out, then open the answer.

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Answer: 2

  1. Height h=Lsin⁡30∘=0.6×0.5=0.3h = L\sin 30^\circ = 0.6 \times 0.5 = 0.3 m.
  2. Rolling solid cylinder: mgh=34mv2⇒v2=43ghmgh = \frac{3}{4}mv^2 \Rightarrow v^2 = \frac{4}{3}gh.
  3. v2=43×10×0.3=4v^2 = \frac{4}{3}\times 10 \times 0.3 = 4
  4. v=2v = 2 m s−1^{-1}.
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