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Rolling Motion question from NEET 2019

Q67NEET 2019Medium

Rolling Motion

A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle of inclination $30^\circ$ . The centre of mass of the cylinder has speed of 4 m/s. The distance travelled by the cylinder on the inclined surface will be, [take $g = 10\text{ m/s}^{2}$ ]

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Answer: (a)

Rolling solid cylinder KE $= \frac{3}{4}mv^2$ becomes $mgd\sin 30^\circ$ .
$\frac{3}{4}\times 4^2 = 10 \times d \times \frac{1}{2} \Rightarrow 12 = 5d$
$d = 2.4$ m.
So the answer is (a).

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