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MHT CET 2024 (4 May, Shift 1) · Rotational Kinetic Energy, Work & Power

Rotational Kinetic Energy, Work & Power question from MHT CET 2024 (4 May, Shift 1)

Q23MHT CET 2024 · 4 MAY · SHIFT 1Medium

Rotational Kinetic Energy, Work & Power

A solid cylinder of mass M and radius R is rotating about its geometrical axis. A solid sphere of the same mass and same radius is also rotating about its diameter with an angular speed half that of the cylinder. The ratio of the kinetic energy of rotation of the sphere to that of the cylinder will be

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Answer: (b)

  1. Cylinder: Kc=12(12MR2)ω2=MR2ω24K_c = \frac{1}{2}\left(\frac{1}{2}MR^2\right)\omega^2 = \frac{MR^2\omega^2}{4}
  2. Sphere at ω2\frac{\omega}{2}: Ks=12(25MR2)ω24=MR2ω220K_s = \frac{1}{2}\left(\frac{2}{5}MR^2\right)\frac{\omega^2}{4} = \frac{MR^2\omega^2}{20}
  3. KsKc=15\frac{K_s}{K_c} = \frac{1}{5}
  4. So the answer is (b) 1:51 : 5.
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