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NEET 1989 (AIPMT) · Rolling Motion

Rolling Motion question from NEET 1989 (AIPMT)

Q95NEET 1989 · AIPMTEasy

Rolling Motion

A solid cylinder of mass $M$ and radius $R$ rolls without slipping down an inclined plane of length $L$ and height $h$ . What is the speed of its centre of mass when the cylinder reaches its bottom?

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Answer: (c)

$Mgh = \frac{1}{2}Mv^2\left(1 + \frac{k^2}{R^2}\right)$ , with $\frac{k^2}{R^2} = \frac{1}{2}$ for a solid cylinder.
$Mgh = \frac{3}{4}Mv^2 \Rightarrow v = \sqrt{\frac{4}{3}gh}$
So the answer is (c) $\sqrt{\frac{4}{3}gh}$ .

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