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MHT CET 2023 (9 May, Shift 1) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from MHT CET 2023 (9 May, Shift 1)

Q71MHT CET 2023 · 9 MAY · SHIFT 1Medium

Electric Flux & Gauss's Law

A solid metallic sphere has a charge +3Q+3Q. Concentric with this sphere is a conducting spherical shell having charge −Q-Q. The radius of the sphere is 'AA' and that of the spherical shell is 'BB'. (B>A)(B > A). The electric field at a distance 'RR' (A<R<B)(A < R < B) from the centre is ( ε0=\varepsilon_0 = permittivity of vacuum)

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Answer: (c)

  1. A Gaussian sphere of radius RR (A<R<BA < R < B) encloses only the inner sphere's charge +3Q+3Q; the shell's charge lies outside.
  2. E=3Q4πε0R2E = \frac{3Q}{4\pi\varepsilon_0 R^2}
  3. So the answer is (c).
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