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JEE Main 2025 (24 Jan, Shift 2) · Rolling Motion

Rolling Motion question from JEE Main 2025 (24 Jan, Shift 2)

Q16JEE Main 2025 · 24 JAN · SHIFT 2Medium

Rolling Motion

A solid sphere and a hollow sphere of the same mass and of same radius are rolled on an inclined plane. Let the time taken to reach the bottom by the solid sphere and the hollow sphere be $t_1$ and $t_2$ , respectively, then

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Answer: (a)

Solid sphere $k^2/R^2 = \frac{2}{5}$ , hollow sphere $k^2/R^2 = \frac{2}{3}$ .
Smaller $k^2/R^2$ gives larger $a = \dfrac{g\sin\theta}{1 + k^2/R^2}$ , so the solid sphere is faster.
So $t_1 < t_2$ : answer (a).

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