A solid sphere isthrotating about a diameter at an angular velocity ω. If it cools so that its radius reduces to (1/n) of its original value, its angular velocity becomes (a) (ω)/(n) (b) ωn² (c) nω (d) n²ω

Answer: (d). Solid sphere: I=25MR²∝ R²; L=Iω is conserved. R/n⇒ I/n² ω'=n²ω So the answer is (d) n²ω.

A solid sphere isthrotating about a diameter at an angular velocity… | MHT CET 2026 (14 May, Shift 2)

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Angular Momentum & its Conservation

A solid sphere isthrotating about a diameter at an angular velocity $\omega$ . If it cools so that its radius reduces to $\left(\frac{1}{n}\right)$ of its original value, its angular velocity becomes

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Answer: (d)

Solid sphere: $I=\frac25MR^2\propto R^2$ ; $L=I\omega$ is conserved.
$R\to\frac{R}{n}\Rightarrow I\to\frac{I}{n^2}$
$\omega'=n^2\omega$
So the answer is (d) $n^2\omega$ .

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