A solid sphere of mass 1 kg rolls without slipping on a plane surface. Its kinetic energy is 7 × 10⁻³ J. The speed of the centre of mass of the sphere is __________ cm s⁻¹ Numerical answer type. Work it out, then open the answer.

Answer: 10. Rolling solid sphere: KE = 7/10mv². 7/10× 1 × v² = 7× 10⁻³ ⇒ v = 0.1 m/s. Speed = 10 cm s ⁻¹.

A solid sphere of mass 1 kg rolls without slipping on a plane… | JEE Main 2023 (31 Jan, Shift 1)

Q41JEE Main 2023 · 31 JAN · SHIFT 1Medium

Rolling Motion

A solid sphere of mass $1\text{ kg}$ rolls without slipping on a plane surface. Its kinetic energy is $7 \times 10^{-3}\text{ J}$ . The speed of the centre of mass of the sphere is __________ $\text{cm s}^{-1}$

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 10

Rolling solid sphere: $KE = \frac{7}{10}mv^2$ .
$\frac{7}{10}\times 1 \times v^2 = 7\times 10^{-3} \Rightarrow v = 0.1$ m/s.
Speed $= 10$ cm s $^{-1}$ .

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