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JEE Main 2023 (29 Jan, Shift 1) · Rolling Motion

Rolling Motion question from JEE Main 2023 (29 Jan, Shift 1)

Q38JEE Main 2023 · 29 JAN · SHIFT 1Easy

Rolling Motion

A solid sphere of mass 2 kg is making pure rolling on a horizontal surface with kinetic energy 2240 J. The velocity of centre of mass of the sphere will be _______ ms $^{-1}$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 40

Rolling solid sphere: $K = \frac{7}{10}mv^2$ .
$2240 = \frac{7}{10}\times 2\times v^2 = 1.4v^2 \Rightarrow v^2 = 1600$
$v = 40$ m/s

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