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MHT CET 2026 (20 Apr, Shift 2) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2026 (20 Apr, Shift 2)

Q17MHT CET 2026 · 20 APR · SHIFT 2Medium

Moment of Inertia & Radius of Gyration

A solid sphere of mass 5 kg and a disc of mass 4 kg have the same radius. The ratio of moment of inertia of the sphere about its tangent to the moment of inertia of the disc about a tangent in its plane will be $x : y$ . The value of $x$ and $y$ respectively is

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Answer: (c)

Sphere about tangent: $\frac{7}{5}MR^2 = \frac{7}{5}(5)R^2 = 7R^2$ .
Disc about tangent in its plane: $\frac{5}{4}MR^2 = \frac{5}{4}(4)R^2 = 5R^2$ .
Ratio $= 7 : 5$ .
So the answer is (c) $7, 5$ .

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