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MHT CET 2026 (16 Apr, Shift 2) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2026 (16 Apr, Shift 2)

Q21MHT CET 2026 · 16 APR · SHIFT 2Medium

Moment of Inertia & Radius of Gyration

A solid sphere of mass M and a disc of mass M2\frac{M}{2} have the same radius. The ratio of moment of inertia of the disc about a tangent in its plane to the moment of inertia of the sphere about its tangent will be

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Answer: (b)

  1. Disc (mass M2\frac{M}{2}), tangent in its plane: 54⋅M2R2=58MR2\frac{5}{4}\cdot\frac{M}{2}R^2 = \frac{5}{8}MR^2.
  2. Sphere, tangent: 75MR2\frac{7}{5}MR^2.
  3. Ratio =5/87/5=2556= \frac{5/8}{7/5} = \frac{25}{56}
  4. So the answer is (b) 25:5625 : 56.
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