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MHT CET 2026 (17 Apr, Shift 2) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2026 (17 Apr, Shift 2)

Q6MHT CET 2026 · 17 APR · SHIFT 2Easy

Moment of Inertia & Radius of Gyration

A solid sphere of radius R and mass M is rotating about its diameter. The moment of intertia of the solid sphere rotating about an axis at a distance R3\frac{R}{3} from the centre and parallel to that diameter is

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Answer: (c)

  1. About a diameter: Icm=25MR2I_{cm} = \frac{2}{5}MR^2.
  2. Parallel axis at R3\frac{R}{3}: I=25MR2+MR29I = \frac{2}{5}MR^2 + \frac{MR^2}{9}
  3. I=18+545MR2=2345MR2I = \frac{18 + 5}{45}MR^2 = \frac{23}{45}MR^2
  4. So the answer is (c) 2345MR2\frac{23}{45}MR^2.
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