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JEE Main 2022 (26 Jun, Shift 2) · Rolling Motion

Rolling Motion question from JEE Main 2022 (26 Jun, Shift 2)

Q48JEE Main 2022 · 26 JUN · SHIFT 2Easy

Rolling Motion

A solid spherical ball is rolling on a frictionless horizontal plane surface about its axis of symmetry. The ratio of rotational kinetic energy of the ball to its total kinetic energy is

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Answer: (b)

$\frac{K_{rot}}{K_{total}} = \frac{k^2/R^2}{1 + k^2/R^2}$
Solid sphere: $\frac{k^2}{R^2} = \frac{2}{5}$ , so ratio $= \frac{2/5}{7/5} = \frac{2}{7}$
So the answer is (b) $\frac{2}{7}$ .

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