A sonometer wire is in unison with a tuning fork, when it is stretched by weight w and the corresponding resonating length is L₁. If the weight is reduced to (w/4), the corresponding resonating length becomes L₂. The ratio ((L₁)/(L₂)) is (a) 4: 1 (b) 1: 4 (c) 1: 2 (d) 2: 1

Answer: (d). Unison with same fork: n=1/2L√(w/μ), so L ∝ √(w). (L₁)/(L₂)=√(w/w/4)=2 So the answer is (d) 2:1.

A sonometer wire is in unison with a tuning fork, when it is… | MHT CET 2019 (3 May, Shift 1)

Q96MHT CET 2019 · 3 MAY · SHIFT 1Medium

Stationary Waves & Vibrating Strings

A sonometer wire is in unison with a tuning fork, when it is stretched by weight $w$ and the corresponding resonating length is $L_1$ . If the weight is reduced to $\left(\frac{w}{4}\right)$ , the corresponding resonating length becomes $L_2$ . The ratio $\left(\frac{L_1}{L_2}\right)$ is

Show answer and solution

Answer: (d)

Unison with same fork: $n=\frac{1}{2L}\sqrt{\frac{w}{\mu}}$ , so $L \propto \sqrt{w}$ .
$\frac{L_1}{L_2}=\sqrt{\frac{w}{w/4}}=2$
So the answer is (d) $2:1$ .

Report a mistake

Stationary Waves & Vibrating Strings question from MHT CET 2019 (3 May, Shift 1)

More questions on Stationary Waves & Vibrating Strings