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MHT CET 2024 (2 May, Shift 2) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from MHT CET 2024 (2 May, Shift 2)

Q55MHT CET 2024 · 2 MAY · SHIFT 2Medium

Stationary Waves & Vibrating Strings

A sonometer wire is stretched by hanging a metal bob. The fundamental frequency of vibration of wire is ' n1n_1 '. When the bob is completely immersed in water, the frequency of vibration of wire becomes ' n2n_2 '. The relative density of the metal of the bob is

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Answer: (c)

  1. n∝Tn \propto \sqrt{T}; the buoyant force reduces tension from VρgV\rho g to V(ρ−ρw)gV(\rho - \rho_w)g.
  2. n22n12=d−1d⇒d=n12n12−n22\dfrac{n_2^2}{n_1^2} = \dfrac{d-1}{d} \Rightarrow d = \dfrac{n_1^2}{n_1^2 - n_2^2}
  3. So the answer is (c).
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