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JEE Main 2024 (5 Apr, Shift 2) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from JEE Main 2024 (5 Apr, Shift 2)

Q45JEE Main 2024 · 5 APR · SHIFT 2Easy

Stationary Waves & Vibrating Strings

A sonometer wire of resonating length 90 cm90\text{ cm} has a fundamental frequency of 400 Hz400\text{ Hz} when kept under some tension. The resonating length of the wire with fundamental frequency of 600 Hz600\text{ Hz} under same tension _______ cm\text{cm}.

Numerical answer type. Work it out, then open the answer.

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Answer: 60

  1. Same tension and wire: f∝1Lf \propto \dfrac{1}{L}.
  2. L2=90×400600=60 cmL_2 = 90 \times \dfrac{400}{600} = 60\text{ cm}.
  3. So the resonating length is 60 cm60\text{ cm}.
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