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MHT CET 2026 (15 Apr, Shift 1) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from MHT CET 2026 (15 Apr, Shift 1)

Q25MHT CET 2026 · 15 APR · SHIFT 1Medium

Stationary Waves & Vibrating Strings

A sonometer wire resonates with 44 antinodes between the two bridges for a given tuning fork when 11 kg mass is suspended from the wire. Using same fork, when mass M is suspended, the wire resonates producing 22 antinodes between the two bridges. (Distance between the bridges as before) The value of M is

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Answer: (c)

  1. Same fork and length: n=p2LMgμ⇒p2M=constantn = \dfrac{p}{2L}\sqrt{\dfrac{Mg}{\mu}} \Rightarrow p^2 M = \text{constant}.
  2. 42×1=22×M⇒M=4 kg4^2 \times 1 = 2^2 \times M \Rightarrow M = 4\text{ kg}
  3. So the answer is (c) 44 kg.
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