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JEE Main 2020 (6 Sep, Shift 1) · Doppler Effect

Doppler Effect question from JEE Main 2020 (6 Sep, Shift 1)

Q50JEE Main 2020 · 6 SEP · SHIFT 1Difficult

Doppler Effect

A sound source S is moving along a straight track with speed v, and is emitting, sound of frequency v0 (see figure). An observer is standing at a finite distance, at the point O, from the track. The time variation of frequency heard by the observer is best represented by:

(t0 represents the instant when the distance between the source and observer is minimum)

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Answer: (d)

  1. Heard frequency ν=ν0vsoundvsound−vcos⁡θ\nu = \frac{\nu_0 v_{sound}}{v_{sound} - v\cos\theta}, where θ\theta is the angle between the source velocity and the line to O.
  2. Far before O: θ≈0\theta \approx 0, so ν\nu is maximum and nearly constant, above ν0\nu_0.
  3. As the source passes, cos⁡θ\cos\theta falls smoothly from +1+1 to −1-1, so ν\nu decreases continuously, through about ν0\nu_0 near t0t_0.
  4. Far after O: ν\nu levels off at a minimum below ν0\nu_0.
  5. So the answer is (d), the smooth decreasing curve.
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