A sound wave is travelling with a frequency of 50 Hz. The phase difference between the two points in the path of a wave is π/3. The distance between those two points is (Velocity of sound in air = 330 m/s) (a) 1.1 m (b) 0.6 m (c) 2.2 m (d) 1.7 m

Answer: (a). λ = v/f = 330/50 = 6.6 m Δφ = π/3 means Δ x = (λ)/(6) = 6.6/6 = 1.1 m So the answer is (a) 1.1 m.

A sound wave is travelling with a frequency of 50 Hz. The phase… | MHT CET 2021 (22 Sep, Shift 1)

Q71MHT CET 2021 · 22 SEP · SHIFT 1Easy

Progressive Wave Equation

A sound wave is travelling with a frequency of $50\text{ Hz}$ . The phase difference between the two points in the path of a wave is $\frac{\pi}{3}$ . The distance between those two points is (Velocity of sound in air $= 330\text{ m/s}$ )

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Answer: (a)

$\lambda = \frac{v}{f} = \frac{330}{50} = 6.6$ m
$\Delta\phi = \frac{\pi}{3}$ means $\Delta x = \frac{\lambda}{6} = \frac{6.6}{6} = 1.1$ m
So the answer is (a) 1.1 m.

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Progressive Wave Equation question from MHT CET 2021 (22 Sep, Shift 1)

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