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MHT CET 2021 (22 Sep, Shift 2) · Progressive Wave Equation

Progressive Wave Equation question from MHT CET 2021 (22 Sep, Shift 2)

Q70MHT CET 2021 · 22 SEP · SHIFT 2Easy

Progressive Wave Equation

A sound wave of frequency $160\text{ Hz}$ has a velocity of $320\text{ m/s}$ . When it travels through air, the particles having a phase difference of $90^\circ$ , are separated by a distance of

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Answer: (a)

$\lambda = \frac{v}{f} = \frac{320}{160} = 2$ m
$90^\circ$ phase difference means $\Delta x = \frac{\lambda}{4} = 0.5$ m
So the answer is (a) 50 cm.

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