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MHT CET 2024 (16 May, Shift 2) · Doppler Effect

Doppler Effect question from MHT CET 2024 (16 May, Shift 2)

Q24MHT CET 2024 · 16 MAY · SHIFT 2Medium

Doppler Effect

A source and listener are both moving towards each other with speed $\frac{V}{10}$ . (where V is speed of sound) If the frequency of sound note emitted by the source is ' $n$ ', then the frequency heard by the listener would be nearly

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Answer: (b)

Both approaching: $n' = n\,\dfrac{V + V_o}{V - V_s}$ .
$n' = n\,\dfrac{1 + 0.1}{1 - 0.1} = \dfrac{11}{9}n \approx 1.22n$
So the answer is (b) $1.22n$ .

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