A source of frequency gives 5 beats/second when sounded with a source of frequency 200 Hz. The second harmonic of frequency 2 of source gives 10 beats/second when sounded with a source of frequency 420 Hz. The value of is (a) 205 Hz (b) 195 Hz (c) 200 Hz (d) 210 Hz

Answer: (a). = 200 ± 5 = 205 or 195 Hz. 2 = 410 or 390 Hz. With 420 Hz: 420 - 410 = 10 beats (390 gives 30). So the answer is (a) 205 Hz.

A source of frequency gives 5 beats/second when sounded with a source… | NEET 1994 (AIPMT)

Q77NEET 1994 · AIPMTMedium

Beats

A source of frequency $\upsilon$ gives 5 beats/second when sounded with a source of frequency $200\text{ Hz}$ . The second harmonic of frequency $2\upsilon$ of source gives 10 beats/second when sounded with a source of frequency $420\text{ Hz}$ . The value of $\upsilon$ is

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Answer: (a)

$\upsilon = 200 \pm 5 = 205$ or $195\text{ Hz}$ .
$2\upsilon = 410$ or $390\text{ Hz}$ .
With 420 Hz: $420 - 410 = 10$ beats (390 gives 30).
So the answer is (a) $205\text{ Hz}$ .

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